The flight time to Lake Oswego from Saint Charles is 3 hours 19 minutes . This is approximate direct flying time, and include average plane speed 510 miles per hour. Total flight distance between Saint Charles, MO and Lake Oswego, OR is about one thousand, seven hundred miles or two thousand, seven hundred and thirty-six km. Real time can be different, and depends on the time of day, the type of aircraft, and can be significantly longer if there are transplants during the flight.
Flying time is about 3 hours 19 minutes
Select arrival and departure cities, current are Saint Charles, MO and OR
This flight will take about three hours nineteen minutes ;
You can buy ticket to plane or drive by car, check ; distance in miles between Saint Charles and Lake Oswego
| Aircraft | Cruising speed | Time |
| Average | 510 mph | 3 hr 19 min |
| Boeing 737 | 515 mph | 3 hr 18 min |
| Boeing 777 | 554 mph | 3 hr 4 min |
| Airbus | 515 mph | 3 hr 18 min |
Dont forget to include time in airport before and after flight.
| Country | USA |
| State | Missouri |
| City | Saint Charles, MO |
| Latitude | 38.78394 |
| Longitude | -90.48123 |
| Country | USA |
| State | Oregon |
| City | Lake Oswego, OR |
| Latitude | 45.42067 |
| Longitude | -122.67065 |
Please note: current air time calculator show approximate distance and time between cities Saint Charles, MO and Lake Oswego, OR. This values can be different if you flight from airports in this cities. To calculate exact time can be shown only when you buy ticket to the plane. We do not guarantee that there is an airline that connects city Saint Charles and Lake Oswego. To find out if there is such a flight use the ticket purchase service.